7x^2+5x+4+6x^2+2x+39=180

Solution for 7x^2+5x+4+6x^2+2x+39=180 equation:

7x^2+5x+4+6x^2+2x+39=180

We move all terms to the left:

7x^2+5x+4+6x^2+2x+39-(180)=0

We add all the numbers together, and all the variables

13x^2+7x-137=0

a = 13; b = 7; c = -137;
Δ = b2-4ac
Δ = 72-4·13·(-137)
Δ = 7173
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7173}=\sqrt{9*797}=\sqrt{9}*\sqrt{797}=3\sqrt{797}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3\sqrt{797}}{2*13}=\frac{-7-3\sqrt{797}}{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3\sqrt{797}}{2*13}=\frac{-7+3\sqrt{797}}{26}
$